AP Physics C: Thermodynamics
Physics-centered review and inquiry covering thermodynamic laws, kinetic theory, ideal gases, work, entropy, p–V graphs, and absolute zero.
What You Should Be Able To Do
- Explain thermodynamics as a physics model connecting energy transfer, particle motion, and macroscopic variables.
- Use \(PV=nRT\) and \(PV=Nk_BT\) correctly with SI units.
- Interpret temperature as a measure of average translational kinetic energy.
- Calculate work from a p–V process using area under a curve or an integral.
- Apply the first and second laws of thermodynamics to simple systems.
- Calculate entropy change for straightforward reversible processes.
- Use pressure-temperature data to estimate absolute zero by extrapolation.
- Distinguish conduction, convection, and radiation as mechanisms of heat transfer and apply Fourier’s law.
- Use \(Q=mL\) to calculate energy involved in phase changes (fusion and vaporization).
- Interpret heating curves and identify regions of phase change versus temperature change.
- Calculate linear and area thermal expansion using \(\Delta L=\alpha L_0 \Delta T\) and \(\Delta A=2\alpha A_0 \Delta T\).
- Solve thermal equilibrium problems where two or more objects exchange heat until reaching a common final temperature.
Glossary of Thermodynamics Terms
The part of the universe selected for analysis.
Everything outside the system that can exchange energy with it.
A quantity determined only by the current state, such as \(P\), \(V\), \(T\), \(N\), and \(U\).
A quantity that depends on the process, not just the endpoints. Heat \(Q\) and work \(W\) are path variables.
A condition where systems have the same temperature and no net heat flows.
Force per unit area. In a gas, pressure comes from molecular collisions with container walls.
A macroscopic measure related to average molecular kinetic energy.
The total microscopic energy stored in the system, including particle kinetic and potential energies.
Energy transferred because of a temperature difference.
Energy transferred by mechanical interaction, such as compression or expansion.
A state function related to energy dispersal and the number of possible microscopic arrangements.
A constant-temperature process.
A process with no heat transfer: \(Q=0\).
A constant-volume process. No \(P\,dV\) work occurs.
A constant-pressure process.
A slow process where the system remains close to equilibrium at each step.
An ideal process that can be reversed without increasing total entropy.
\(0\ \text{K}\), or \(-273.15^\circ\text{C}\), the theoretical lower limit of temperature.
\(k_B=1.38\times10^{-23}\ \text{J/K}\), connecting temperature to microscopic particle energy.
Heat transfer through direct molecular contact within a material or between materials in contact.
Heat transfer by the bulk movement of a fluid (liquid or gas) carrying thermal energy.
Heat transfer via electromagnetic waves. No medium is required.
The energy required to raise \(1\ \text{kg}\) of a substance by \(1\ \text{K}\). Symbol: \(c\).
The energy per unit mass absorbed or released during a phase change at constant temperature. Symbol: \(L\).
The latent heat for the solid–liquid transition. Symbol: \(L_f\).
The latent heat for the liquid–gas transition. Symbol: \(L_v\).
A transition between solid, liquid, and gas states. Temperature remains constant during phase changes.
The tendency of matter to increase in size when heated, due to increased molecular motion.
The fractional change in length per degree of temperature change. Symbol: \(\alpha\).
The Laws of Thermodynamics
Zeroth Law
If system A is in thermal equilibrium with system B, and B is in thermal equilibrium with system C, then A and C are in thermal equilibrium with each other. This is why thermometers work.
First Law
This version uses \(W_{\text{on}}\), the work done on the system. If work is done by the system, then \(W_{\text{on}}\) is negative.
Second Law
For any real process, the total entropy of the universe does not decrease:
Third Law
As a perfect crystal approaches absolute zero, its entropy approaches a minimum value. In practice, no physical process can cool a system all the way to \(0\ \text{K}\).
The Ideal Gas Law from a Physics Perspective
The chemistry form of the ideal gas law is:
The physics form is often more useful because it describes particles directly:
Macroscopic Meaning
- \(P\): pressure in pascals \((\text{N/m}^2)\)
- \(V\): volume in cubic meters \((\text{m}^3)\)
- \(T\): absolute temperature in kelvin
- \(n\): moles of gas
- \(N\): number of gas particles
Microscopic Meaning
- Pressure comes from particles colliding with walls.
- Temperature measures average translational kinetic energy.
- Volume gives particles more or less space to move.
- More particles means more wall collisions.
Connecting Moles and Particles
where \(N_A=6.022\times10^{23}\ \text{particles/mol}\). Since \(R=N_Ak_B\), the two forms of the ideal gas law are the same physics written at different scales.
Common Physics Mistakes
- Using Celsius in \(PV=nRT\). Temperature must be in kelvin.
- Using liters instead of cubic meters without converting.
- Thinking gas particles push continuously on the walls. The force comes from many tiny impulse collisions.
- Thinking ideal gas particles have no energy. They have kinetic energy; they are assumed to have negligible intermolecular potential energy.
Kinetic Theory of Gases
Kinetic theory explains thermodynamics using Newtonian mechanics and statistics. For an ideal monatomic gas:
The total internal energy is:
A deeper kinetic theory result connects pressure to molecular speed:
This says pressure increases when particles are more massive, more numerous, moving faster, or confined to a smaller volume.
Quick Kinetic Theory Check
A sealed rigid container of ideal gas is heated from \(300\ \text{K}\) to \(600\ \text{K}\). What happens to pressure and average kinetic energy?
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Calculus-Based Work in Thermodynamics
For a quasi-static expansion or compression, the work done by a gas is the area under the \(P\)-versus-\(V\) graph:
Using work done on the gas:
Example: Variable Pressure Work
A gas expands according to \(P(V)=\frac{5000}{V}\), where \(P\) is in pascals and \(V\) is in cubic meters. Find the work done by the gas as it expands from \(1.0\ \text{m}^3\) to \(4.0\ \text{m}^3\).
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Example: Work from a Linear p–V Path
A gas expands from \(V=2.0\ \text{m}^3\) to \(V=6.0\ \text{m}^3\). Its pressure decreases linearly from \(500\ \text{kPa}\) to \(100\ \text{kPa}\). Find the work done by the gas.
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Entropy and the Second Law
Entropy change for a reversible process is calculated using:
For a constant-temperature reversible process:
For heating or cooling a substance with approximately constant specific heat:
Example: Entropy Change During Cooling
A \(2.0\ \text{kg}\) aluminum block cools from \(400\ \text{K}\) to \(300\ \text{K}\). Use \(c=900\ \text{J/(kg\cdot K)}\). Find the entropy change of the block.
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Example: Isothermal Expansion Entropy
One mole of ideal gas expands isothermally at \(300\ \text{K}\) from \(2.0\ \text{L}\) to \(8.0\ \text{L}\). Find \(\Delta S\).
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Heat Transfer
Heat flows from hotter objects to cooler objects through three mechanisms: conduction, convection, and radiation. The quantity of heat transferred to change the temperature of a substance (without a phase change) is:
where \(m\) is the mass, \(c\) is the specific heat capacity, and \(\Delta T = T_f - T_i\).
Conduction
Conduction is heat transfer through direct molecular contact. Energy passes from faster-vibrating molecules to slower ones. Fourier’s law gives the rate of heat flow through a material:
where \(k\) is the thermal conductivity of the material (W/(m·K)), \(A\) is the cross-sectional area, \(\Delta T\) is the temperature difference across the material, and \(L\) is the thickness.
Convection
Convection is heat transfer by the bulk motion of a fluid. Warmer fluid is less dense and rises, while cooler fluid sinks, setting up convection currents. Convection can be natural (driven by buoyancy) or forced (driven by a fan or pump).
Radiation
All objects with temperature above absolute zero emit electromagnetic radiation. The power radiated by an object is given by the Stefan–Boltzmann law:
where \(\varepsilon\) is emissivity (0 to 1), \(\sigma = 5.67\times10^{-8}\ \text{W/(m}^2\text{K}^4)\) is the Stefan–Boltzmann constant, \(A\) is the surface area, and \(T\) is the absolute temperature in kelvin. Dark, rough surfaces have higher emissivity than shiny, polished surfaces.
Problem: Conduction Through a Window
A glass window is \(1.2\ \text{m}\) wide, \(1.5\ \text{m}\) tall, and \(0.005\ \text{m}\) thick. The inside surface is at \(20^\circ\text{C}\) and the outside surface is at \(-5^\circ\text{C}\). The thermal conductivity of glass is \(k=0.80\ \text{W/(m\cdot K)}\). Find the rate of heat loss through the window.
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Problem: Heating Water
How much heat is required to raise the temperature of \(0.500\ \text{kg}\) of water from \(20.0^\circ\text{C}\) to \(85.0^\circ\text{C}\)? Use \(c_{\text{water}}=4186\ \text{J/(kg\cdot K)}\).
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Phase Changes and Latent Heat
Matter exists in three common phases: solid, liquid, and gas. Transitions between these phases are called phase changes. During a phase change, energy is absorbed or released while the temperature remains constant. The energy goes into breaking or forming intermolecular bonds rather than changing molecular kinetic energy.
Key Phase Transitions
Solid → Liquid. Absorbs energy (endothermic).
Liquid → Solid. Releases energy (exothermic).
Liquid → Gas. Absorbs energy (endothermic).
Gas → Liquid. Releases energy (exothermic).
Solid → Gas directly. Absorbs energy.
Gas → Solid directly. Releases energy.
Latent Heat
The energy required for a phase change is calculated using:
where \(m\) is the mass and \(L\) is the latent heat (specific to the substance and the transition). The temperature does not change during this process.
Heat of Fusion (\(L_f\))
The latent heat of fusion is the energy per unit mass required to change a substance from solid to liquid (or released going from liquid to solid) at its melting point:
For water, \(L_f=3.34\times10^5\ \text{J/kg}\) at \(0^\circ\text{C}\). This means it takes \(334\ \text{kJ}\) to melt \(1\ \text{kg}\) of ice at \(0^\circ\text{C}\) into water at \(0^\circ\text{C}\).
Heat of Vaporization (\(L_v\))
The latent heat of vaporization is the energy per unit mass required to change a substance from liquid to gas (or released going from gas to liquid) at its boiling point:
For water, \(L_v=2.26\times10^6\ \text{J/kg}\) at \(100^\circ\text{C}\). This is nearly seven times larger than \(L_f\), because converting liquid to gas requires completely separating molecules from their neighbors.
Heating Curves
A heating curve plots temperature versus heat added for a substance. It has five distinct regions for a substance going from solid to gas:
- Solid heating: Temperature rises. Use \(Q=mc_{\text{solid}}\Delta T\).
- Melting plateau: Temperature stays at the melting point. Use \(Q=mL_f\).
- Liquid heating: Temperature rises. Use \(Q=mc_{\text{liquid}}\Delta T\).
- Boiling plateau: Temperature stays at the boiling point. Use \(Q=mL_v\).
- Gas heating: Temperature rises. Use \(Q=mc_{\text{gas}}\Delta T\).
Problem: Melting Ice
How much energy is needed to melt \(0.200\ \text{kg}\) of ice at \(0^\circ\text{C}\) into water at \(0^\circ\text{C}\)?
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Problem: Boiling Water
How much energy is needed to completely vaporize \(0.150\ \text{kg}\) of water already at \(100^\circ\text{C}\)?
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Problem: Full Heating Curve Calculation
Calculate the total energy needed to convert \(0.100\ \text{kg}\) of ice at \(-20^\circ\text{C}\) to steam at \(120^\circ\text{C}\). Use: \(c_{\text{ice}}=2090\ \text{J/(kg\cdot K)}\), \(L_f=3.34\times10^5\ \text{J/kg}\), \(c_{\text{water}}=4186\ \text{J/(kg\cdot K)}\), \(L_v=2.26\times10^6\ \text{J/kg}\), \(c_{\text{steam}}=2010\ \text{J/(kg\cdot K)}\).
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Thermal Expansion
Most materials expand when heated because increased thermal energy causes atoms to vibrate with larger amplitude around their equilibrium positions. Thermal expansion is important in engineering: bridges have expansion joints, railroad tracks are laid with gaps, and concrete highways have relief joints.
Linear Expansion (One Dimension)
For a solid object with initial length \(L_0\), the change in length due to a temperature change \(\Delta T\) is:
where \(\alpha\) is the coefficient of linear expansion in units of \(1/\text{K}\) or \(1/{}^\circ\text{C}\). The new length is:
Area Expansion (Two Dimensions)
For a flat surface or sheet with initial area \(A_0\), the change in area is approximately:
This approximation comes from expanding both length and width: if \(L\) and \(W\) each grow by a factor of \((1+\alpha\,\Delta T)\), then:
The \(\alpha^2(\Delta T)^2\) term is negligibly small for typical temperature changes.
Problem: Expanding Steel Bridge
A steel bridge span is \(200.0\ \text{m}\) long at \(15^\circ\text{C}\). How much longer is it on a \(40^\circ\text{C}\) summer day? Use \(\alpha_{\text{steel}}=12\times10^{-6}\ /{}^\circ\text{C}\).
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Problem: Area Expansion of an Aluminum Sheet
A square aluminum sheet has sides of \(1.00\ \text{m}\) at \(20^\circ\text{C}\). By how much does its area increase when heated to \(120^\circ\text{C}\)? Use \(\alpha_{\text{Al}}=23\times10^{-6}\ /{}^\circ\text{C}\).
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Constants and Known Values
Reference tables for thermodynamics calculations. Values are approximate and at standard conditions unless noted.
Fundamental Constants
| Constant | Symbol | Value |
|---|---|---|
| Boltzmann constant | \(k_B\) | \(1.38\times10^{-23}\ \text{J/K}\) |
| Universal gas constant | \(R\) | \(8.314\ \text{J/(mol\cdot K)}\) |
| Avogadro’s number | \(N_A\) | \(6.022\times10^{23}\ \text{mol}^{-1}\) |
| Stefan–Boltzmann constant | \(\sigma\) | \(5.67\times10^{-8}\ \text{W/(m}^2\text{K}^4)\) |
| Standard atmospheric pressure | \(P_0\) | \(1.013\times10^5\ \text{Pa}\) |
Specific Heat Capacities
| Substance | \(c\) (J/(kg·K)) |
|---|---|
| Water (liquid) | 4186 |
| Ice | 2090 |
| Steam | 2010 |
| Aluminum | 900 |
| Copper | 385 |
| Iron / Steel | 450 |
| Lead | 128 |
| Glass | 840 |
| Ethanol | 2440 |
| Air (at constant pressure) | 1005 |
Latent Heats
| Substance | Melting Point (°C) | \(L_f\) (J/kg) | Boiling Point (°C) | \(L_v\) (J/kg) |
|---|---|---|---|---|
| Water | 0 | \(3.34\times10^5\) | 100 | \(2.26\times10^6\) |
| Ethanol | −114 | \(1.09\times10^5\) | 78 | \(8.46\times10^5\) |
| Lead | 327 | \(2.45\times10^4\) | 1750 | \(8.70\times10^5\) |
| Aluminum | 660 | \(3.97\times10^5\) | 2519 | \(1.07\times10^7\) |
| Copper | 1085 | \(2.07\times10^5\) | 2562 | \(4.73\times10^6\) |
| Nitrogen | −210 | \(2.56\times10^4\) | −196 | \(2.01\times10^5\) |
| Oxygen | −219 | \(1.39\times10^4\) | −183 | \(2.13\times10^5\) |
Thermal Conductivities
| Material | \(k\) (W/(m·K)) |
|---|---|
| Silver | 429 |
| Copper | 401 |
| Aluminum | 237 |
| Iron / Steel | 80 |
| Glass | 0.80 |
| Concrete | 0.80 |
| Wood | 0.08–0.16 |
| Styrofoam | 0.033 |
| Air | 0.026 |
Coefficients of Linear Expansion
| Material | \(\alpha\) (\(\times10^{-6}\)/°C) |
|---|---|
| Aluminum | 23 |
| Brass | 19 |
| Copper | 17 |
| Iron / Steel | 12 |
| Glass (ordinary) | 9 |
| Glass (Pyrex) | 3.2 |
| Concrete | 12 |
| Lead | 29 |
| Invar (nickel-iron alloy) | 0.9 |
Thermal Equilibrium Problems
When two or more objects at different temperatures are placed in thermal contact (and insulated from the surroundings), heat flows from the hotter object to the cooler one until they reach a common final temperature \(T_f\). By conservation of energy:
or equivalently, the total heat gained by cooler objects equals the total heat lost by warmer objects:
Problem: Two Metals Reaching Equilibrium
A \(0.300\ \text{kg}\) copper block at \(250^\circ\text{C}\) is dropped into \(0.500\ \text{kg}\) of water at \(20.0^\circ\text{C}\) in an insulated container. Find the final equilibrium temperature. Use \(c_{\text{Cu}}=385\ \text{J/(kg\cdot K)}\) and \(c_{\text{water}}=4186\ \text{J/(kg\cdot K)}\).
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Problem: Ice Added to Warm Water
\(0.050\ \text{kg}\) of ice at \(0^\circ\text{C}\) is added to \(0.400\ \text{kg}\) of water at \(35.0^\circ\text{C}\) in an insulated cup. Find the final temperature. Assume all ice melts. Use \(L_f=3.34\times10^5\ \text{J/kg}\), \(c_{\text{water}}=4186\ \text{J/(kg\cdot K)}\).
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Problem: Three-Object Equilibrium
An insulated container holds \(0.200\ \text{kg}\) of water at \(25.0^\circ\text{C}\). A \(0.150\ \text{kg}\) aluminum block at \(90.0^\circ\text{C}\) and a \(0.100\ \text{kg}\) iron block at \(200^\circ\text{C}\) are both dropped in simultaneously. Find the final equilibrium temperature. Use \(c_{\text{water}}=4186\ \text{J/(kg\cdot K)}\), \(c_{\text{Al}}=900\ \text{J/(kg\cdot K)}\), \(c_{\text{Fe}}=450\ \text{J/(kg\cdot K)}\).
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Graph Interpretation
p–V Graphs
On a p–V diagram, what does the area under a process curve represent?
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Cycles
A closed loop on a p–V diagram represents a heat engine cycle. What does the area inside the loop represent?
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Heating Curves
A temperature-versus-time graph has a flat region while heat is still being added. What does this mean?
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Inquiry Lab: Determining Absolute Zero
Purpose
Use pressure-temperature data for a fixed-volume gas to estimate absolute zero. You will generate your own graph, determine a best-fit line, and extrapolate to the temperature where pressure would become zero.
Physics Background
For a fixed amount of gas at constant volume:
Since kelvin temperature is related to Celsius temperature by:
a graph of pressure \(P\) versus Celsius temperature \(T_C\) should be approximately linear. If the line is extended until \(P=0\), the x-intercept estimates absolute zero.
Provided Data Set
| Temperature, \(T_C\) (°C) | Pressure, \(P\) (kPa) |
|---|---|
| −50 | 81.2 |
| −25 | 89.0 |
| 0 | 98.3 |
| 25 | 107.2 |
| 50 | 116.0 |
| 75 | 125.1 |
| 100 | 133.9 |
Student Tasks
- Plot pressure \(P\) on the vertical axis and Celsius temperature \(T_C\) on the horizontal axis.
- Draw or calculate a best-fit line.
- Write the equation of your line in the form \(P=mT_C+b\).
- Set \(P=0\) and solve for the x-intercept.
- Use the x-intercept as your experimental estimate of absolute zero.
- Calculate percent error using \(-273.15^\circ\text{C}\) as the accepted value.
- Explain why this experiment supports using the kelvin temperature scale.
Blank Graph Space
Use this space if printing, or recreate it in your notebook or spreadsheet.
Analysis Questions
- What physical variable was held constant in this experiment?
- Why should pressure decrease as temperature decreases?
- Why is it reasonable to extrapolate the trend even though no data was collected near \(-273^\circ\text{C}\)?
- Why would a real gas stop behaving ideally before reaching absolute zero?
- How would random measurement error affect the x-intercept?
Teacher Check: Expected Result
Practice Problems with Hidden Solutions
Problem 1: Ideal Gas Calculation
A container holds \(0.50\ \text{mol}\) of ideal gas at \(300\ \text{K}\) in a volume of \(0.012\ \text{m}^3\). Find the pressure.
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Problem 2: First Law
A gas absorbs \(500\ \text{J}\) of heat and does \(200\ \text{J}\) of work on its surroundings. Find \(\Delta U\).
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Problem 3: RMS Speed
For a gas molecule of mass \(4.65\times10^{-26}\ \text{kg}\) at \(300\ \text{K}\), find the rms speed.
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Problem 4: Entropy of Heat Transfer
A reservoir at \(400\ \text{K}\) loses \(1200\ \text{J}\) of heat. What is its entropy change?
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Problem 5: Conduction Rate
A copper rod is \(0.50\ \text{m}\) long and has a cross-sectional area of \(1.0\times10^{-4}\ \text{m}^2\). One end is held at \(100^\circ\text{C}\) and the other at \(0^\circ\text{C}\). Find the rate of heat transfer. Use \(k_{\text{Cu}}=401\ \text{W/(m\cdot K)}\).
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Problem 6: Latent Heat of Fusion
A \(0.500\ \text{kg}\) block of lead at its melting point (\(327^\circ\text{C}\)) is completely melted. How much energy was absorbed? Use \(L_f=2.45\times10^4\ \text{J/kg}\).
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Problem 7: Linear Thermal Expansion
A brass rod is \(1.500\ \text{m}\) at \(20^\circ\text{C}\). What is its length at \(180^\circ\text{C}\)? Use \(\alpha_{\text{brass}}=19\times10^{-6}\ /{}^\circ\text{C}\).
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Problem 8: Thermal Equilibrium
A \(0.250\ \text{kg}\) iron horseshoe at \(500^\circ\text{C}\) is plunged into \(2.00\ \text{kg}\) of water at \(22.0^\circ\text{C}\) in an insulated bucket. Find the final temperature. Use \(c_{\text{Fe}}=450\ \text{J/(kg\cdot K)}\) and \(c_{\text{water}}=4186\ \text{J/(kg\cdot K)}\).
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Problem 9: Phase Change Energy
How much total energy is needed to convert \(0.300\ \text{kg}\) of ice at \(-10^\circ\text{C}\) into water at \(25^\circ\text{C}\)? Use \(c_{\text{ice}}=2090\ \text{J/(kg\cdot K)}\), \(L_f=3.34\times10^5\ \text{J/kg}\), \(c_{\text{water}}=4186\ \text{J/(kg\cdot K)}\).
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Check Understanding
Use these quick checks to test the main ideas. Your score is not saved.
1. In the ideal gas law, which temperature scale must be used?
2. On a p–V graph, the area under the curve represents:
3. If an ideal gas is held at constant volume and temperature doubles in kelvin, pressure:
4. For an ideal monatomic gas, internal energy depends directly on:
5. A real irreversible process has:
6. Which mechanism of heat transfer does NOT require a medium?
7. During a phase change, the temperature of the substance:
8. For water, the heat of vaporization compared to the heat of fusion is:
9. A steel beam expands when heated. If the temperature change doubles, the expansion:
10. For area expansion of a flat sheet, the coefficient is approximately:
11. When a hot metal block is placed in cool water in an insulated container, at equilibrium:
12. In Fourier’s law of conduction, doubling the thickness of a wall while keeping everything else the same will: