Geometry • Unit 3

Polygons & Parallel Lines

Angles start inside polygons, move outside triangles, then travel through parallel lines and transversals. Those same relationships become the rules for parallelograms and trapezoids. The unit is really one connected idea: use structure to decide which angles or lengths must match, add to 180°, or satisfy an inequality.

Lesson Map

This follows the sequence in the Unit 3 lesson materials and emphasizes the skills that appear on the unit assessment.

LessonFocusThe skill being checked
Lesson 1Sum of interior anglesUse (n − 2)180° to find an angle sum, solve for a missing angle, or work backward to find the number of sides.
Lesson 2Regular polygonsFind each interior and exterior angle of a regular polygon and solve backward from an angle measure to n.
Lesson 3Triangle inequalitiesUse the exterior angle theorem, order sides and angles, test possible triangles, and find the range of a third side.
Lesson 4 — Day 1Vertical angles & angle pairsName corresponding, alternate interior/exterior, and same-side interior angle pairs; use vertical and linear-pair relationships.
Lesson 4 — Day 2Parallel lines & transversalsUse congruent or supplementary angle relationships created by parallel lines to solve algebraic equations.
Lesson 5 — ParallelogramsProperties of parallelogramsUse opposite sides/angles, consecutive angles, and bisected diagonals to find missing values.
Lesson 5 — TrapezoidsIsosceles trapezoids & midsegmentsUse base-angle and diagonal theorems plus the trapezoid midsegment formula.
Performance TaskCity DesignBuild a street map that demonstrates parallel lines, transversals, angle-pair vocabulary, and required polygon types.
AssessmentUnit 3 reviewCombine polygon formulas, triangle inequalities, transversal relationships, parallelograms, and trapezoids in multi-step problems.

Content Summary

Start by identifying the structure in the figure. Once you know what kind of polygon, triangle, or angle pair you have, the equation usually follows immediately.

Lesson 1

Interior Angles of Polygons

A convex polygon has every interior angle less than 180°. A concave polygon has at least one interior angle greater than 180°. The Unit 3 formula is for the sum of the interior angles of a convex polygon.

Sum of interior angles = (n − 2) × 180°

Why n − 2? From one vertex, a convex n-gon can be divided into exactly n − 2 non-overlapping triangles. Each contributes 180°.

6 sides → 4 triangles → 4(180°) = 720°

A hexagon can be split into 6 − 2 = 4 triangles, so its interior angles total 720°.

Worked example

A polygon has an interior-angle sum of 1980°. How many sides?

(n − 2)180 = 1980  →  n − 2 = 11  →  n = 13
The mistake to avoid: 1980 ÷ 180 gives n − 2, not n. Add 2 at the end.
Lesson 2

Regular Polygons

A regular polygon has all sides congruent and all interior angles congruent. That means you can divide the total interior-angle sum evenly among the n angles.

Each interior angle = ((n − 2) × 180°) ÷ n
Each exterior angle = 360° ÷ n

An interior angle and its adjacent exterior angle form a linear pair, so they always add to 180°.

interior + exterior = 180°

Worked example

Find each interior and exterior angle of a regular octagon.

Interior = (6 × 180°) ÷ 8 = 135°   |   Exterior = 360° ÷ 8 = 45°
Fast backward method: if a regular polygon has exterior angle 20°, then n = 360 ÷ 20 = 18. This is faster than solving the interior-angle formula.
Lesson 3

Inequalities in Triangles

Exterior Angle Theorem

An exterior angle of a triangle equals the sum of its two remote interior angles.

exterior angle = remote interior angle + remote interior angle

Side–Angle Inequality

In one triangle, the larger angle is opposite the longer side. The smaller angle is opposite the shorter side. This lets you order sides from angle measures or order angles from side lengths.

A B C 18 21 27 largest side ↔ largest angle

Match an angle to the side directly opposite it — not to a side touching the angle.

Triangle Inequality Theorem

The sum of any two sides of a triangle must be greater than the third. When two side lengths are known, the third side x must satisfy:

|a − b| < x < a + b

Example: if two sides are 12 and 25, then 13 < x < 37. The endpoints are not included, because equality would make a straight segment rather than a triangle.

Lesson 4

Vertical Angles, Angle Pairs & Parallel Lines

When a transversal crosses two lines, the locations of the angles give each pair a name. When the two lines are parallel, those names tell you whether the angles are congruent or supplementary.

1 2 3 4 5 6 7 8 ℓ m transversal

Use position first to name the pair. Then use parallel-line rules to decide congruent or supplementary.

Vertical angles

Opposite angles at one intersection. Always congruent.

Linear pair

Adjacent angles forming a straight line. Always supplementary.

Corresponding

Same relative corner at the two intersections. Congruent if the lines are parallel.

Alternate interior

Inside the parallel lines, opposite sides of the transversal. Congruent.

Alternate exterior

Outside the parallel lines, opposite sides of the transversal. Congruent.

Same-side interior

Inside the parallel lines, same side of the transversal. Supplementary.

Do not start with algebra. First name the relationship. “Alternate interior” tells you to set the expressions equal; “same-side interior” tells you to make their sum 180°.
Lesson 5

Parallelograms

A parallelogram is a quadrilateral with both pairs of opposite sides parallel. Because each pair of sides acts as parallel lines cut by transversals, the angle rules from Lesson 4 generate the parallelogram theorems.

Opposite sides

Congruent.

Opposite angles

Congruent.

Consecutive angles

Supplementary.

Diagonals

Bisect each other.

A B C D M AM = MC and BM = MD

Worked example

If ∠A = 56°, then ∠C = 56° because opposite angles are congruent. ∠B and ∠D are each 124° because consecutive angles are supplementary.

Lesson 5

Trapezoids & Midsegments

A trapezoid has one pair of parallel sides, called the bases. In an isosceles trapezoid, the legs are congruent. Its base angles are congruent and its diagonals are congruent.

base b₁ base b₂ midsegment
Trapezoid midsegment = (base₁ + base₂) ÷ 2

Worked example

Bases are 59 and 17. The midsegment is:

(59 + 17) ÷ 2 = 76 ÷ 2 = 38
Connection to Lesson 4: angles along the same leg between the two parallel bases are same-side interior angles, so they are supplementary.

Vocabulary

These words tell you what relationship to use. Being precise with vocabulary is part of getting the equation right.

Polygon

A closed plane figure made from straight line segments.

Convex polygon

A polygon whose interior angles are all less than 180°.

Concave polygon

A polygon with at least one interior angle greater than 180°.

Regular polygon

A polygon with all sides congruent and all angles congruent.

Interior angle

An angle formed inside a polygon by two adjacent sides.

Exterior angle

An angle formed outside a polygon by one side and the extension of an adjacent side.

Remote interior angles

The two triangle angles not adjacent to a chosen exterior angle.

Triangle inequality

The sum of any two side lengths of a triangle must be greater than the third.

Transversal

A line that intersects two or more coplanar lines at different points.

Vertical angles

Opposite angles formed by two intersecting lines; they are congruent.

Corresponding angles

Angles in the same relative position at two intersections.

Alternate interior angles

Interior angles on opposite sides of a transversal.

Alternate exterior angles

Exterior angles on opposite sides of a transversal.

Same-side interior angles

Interior angles on the same side of a transversal; supplementary when the lines are parallel.

Parallelogram

A quadrilateral with both pairs of opposite sides parallel.

Trapezoid

A quadrilateral with one pair of parallel sides.

Isosceles trapezoid

A trapezoid with congruent legs; each pair of base angles is congruent.

Midsegment of a trapezoid

The segment joining the midpoints of the legs; its length is the average of the two bases.

Sample Problems

Twelve problems in homework and assessment format, grouped by lesson. Work each one on paper first — the solutions are one click away, which makes them very easy to read too early.

Lesson 1 — Interior Angles of Polygons

1

Polygon angle sum

Find the sum of the interior angles of a 20-sided polygon.

Show solution
(20 − 2)180 = 18(180) = 3240°
2

Work backward from the sum

The interior angles of a polygon total 4860°. How many sides does it have?

Show solution
(n − 2)180 = 4860  →  n − 2 = 27  →  n = 29

Lesson 2 — Regular Polygons

3

Regular polygon

Find each interior angle and each exterior angle of a regular 12-gon.

Show solution
Interior = (10 × 180) ÷ 12 = 150°   |   Exterior = 360 ÷ 12 = 30°
4

Regular polygon from an exterior angle

Each exterior angle of a regular polygon measures 40°. How many sides?

Show solution
n = 360 ÷ 40 = 9

Lesson 3 — Inequalities in Triangles

5

Exterior Angle Theorem

A triangle has remote interior angles of 48° and 67°. Find the exterior angle.

Show solution
48° + 67° = 115°
6

Triangle inequality range

Two sides of a triangle are 11 and 20. Between what two values must the third side x fall?

Show solution
|20 − 11| < x < 20 + 11  →  9 < x < 31
7

Order the sides

In △ABC, ∠A = 41°, ∠B = 63°, and ∠C = 76°. List the sides from shortest to longest.

Show solution

The smallest angle A is opposite BC; B is opposite AC; the largest angle C is opposite AB.

BC < AC < AB

Lesson 4 — Angle Pairs, Parallel Lines & Transversals

8

Vertical angles

Two vertical angles are labeled 6x − 21 and 105°. Find x.

Show solution
6x − 21 = 105  →  6x = 126  →  x = 21
9

Parallel lines: same-side interior

Two same-side interior angles are 4x − 12 and 120°. The lines are parallel. Find x.

Show solution

Same-side interior angles are supplementary, so the two expressions add to 180° rather than being set equal.

(4x − 12) + 120 = 180  →  4x = 72  →  x = 18

Lesson 5 — Parallelograms, Trapezoids & Midsegments

10

Parallelogram angles

In parallelogram ABCD, m∠A = 56°. Find B, C, and D.

Show solution

Opposite angles are congruent; consecutive angles are supplementary.

B = 124°,   C = 56°,   D = 124°
11

Parallelogram diagonals

The diagonals bisect each other. If one diagonal is split into segments 4x − 11 and x + 10, find x.

Show solution
4x − 11 = x + 10  →  3x = 21  →  x = 7
12

Trapezoid midsegment

A trapezoid has bases 12 and 26. Find its midsegment.

Show solution
(12 + 26) ÷ 2 = 19

Equations & Rules

Every formula and rule for the unit on one printable page.

Polygon interior sum

S = (n − 2)180°

Regular polygon interior angle

I = ((n − 2)180°) ÷ n

Regular polygon exterior angle

E = 360° ÷ n

Interior/exterior pair

I + E = 180°

Triangle exterior angle

Exterior = remote₁ + remote₂

Third side range

|a − b| < x < a + b

Parallel-line congruent pairs

Corresponding, alternate interior, and alternate exterior angles.

Parallel-line supplementary pair

Same-side interior angles sum to 180°.

Parallelogram

Opposite sides congruent, opposite angles congruent, consecutive angles supplementary, diagonals bisect each other.

Trapezoid midsegment

m = (b₁ + b₂) ÷ 2

Video Library

Walkthroughs matched to the lessons in this unit, mostly Khan Academy. Use them after a first attempt, not instead of one. Videos do not appear on the printed copy.

Lesson 1 — Interior Angles of Polygons

Lesson 1 — where (n − 2)180 comes from Sum of interior angles of a polygon Khan Academy Open the video →
Lesson 1 — the formula on any polygon Sum of Interior Angles of Any Polygon Khan Academy Open the video →
Lesson 1 — naming polygons by side count Introduction to Polygons Mathispower4u Open the video →
Lesson 1 — convex vs. concave Classifying Polygons Mathispower4u Open the video →
Lesson 1 — solving for a missing angle Find the measure of an interior angle of a quadrilateral Mathispower4u Open the video →

Lesson 2 — Regular Polygons

Lesson 2 — both formulas together Interior and Exterior Angles of a Polygon Mathispower4u Open the video →
Lesson 2 — why exterior angles total 360° Sum of the exterior angles of a convex polygon Khan Academy Open the video →
Lesson 2 — worked exterior-angle problems CA Geometry: Exterior angles Khan Academy Open the video →
Lesson 2 — working backward to n Interior and exterior angles of a regular polygon The Organic Chemistry Tutor Open the video →

Lesson 3 — Inequalities in Triangles

Lesson 3 — remote interior angles Introduction to the interior and exterior angles of a triangle Mathispower4u Open the video →
Lesson 3 — why the theorem works Proof: The Exterior Angles Theorem Mathispower4u Open the video →
Lesson 3 — worked example Find an interior angle of a triangle using an exterior angle Mathispower4u Open the video →
Lesson 3 — the third-side range Triangle inequality theorem Khan Academy Open the video →
Lesson 3 — largest side, largest angle Ordering triangle sides and angles Khan Academy Open the video →

Lesson 4 Day 1 — Vertical Angles & Angle Pairs

Lesson 4 Day 1 — naming vertical angles Introduction to vertical angles Khan Academy Open the video →
Lesson 4 Day 1 — why they are congruent Proof: Vertical angles are equal Khan Academy Open the video →
Lesson 4 Day 1 — linear pairs Complementary and supplementary angles Khan Academy Open the video →
Lesson 4 Day 1 — solving a linear pair Find the measure of supplementary angles Khan Academy Open the video →

Lesson 4 Day 2 — Parallel Lines & Transversals

Lesson 4 Day 2 — the six angle pairs Angles formed by parallel lines and transversals Khan Academy Open the video →
Lesson 4 Day 2 — reading the diagram Angles formed between transversals and parallel lines Khan Academy Open the video →
Lesson 4 Day 2 — set equal, or sum to 180° Using algebra to find measures of angles formed from a transversal Khan Academy Open the video →
Lesson 4 Day 2 — quick worked example Figuring out angles between a transversal and parallel lines Khan Academy Open the video →
Lesson 4 Day 2 — multi-step practice Angles of parallel lines 2 Khan Academy Open the video →

Lesson 5 — Parallelograms

Lesson 5 — where a parallelogram fits Quadrilateral properties Khan Academy Open the video →
Lesson 5 — opposite sides Proof: Opposite sides of a parallelogram are congruent Khan Academy Open the video →
Lesson 5 — opposite angles Proof: Opposite angles of a parallelogram are congruent Khan Academy Open the video →
Lesson 5 — the diagonals Proof: Diagonals of a parallelogram bisect each other Khan Academy Open the video →

Lesson 5 — Trapezoids & Midsegments

Lesson 5 — trapezoid vs. parallelogram Quadrilateral relationships: trapezoids and parallelograms Khan Academy Open the video →
Lesson 5 — base angles and diagonals Isosceles Trapezoids The Organic Chemistry Tutor Open the video →
Lesson 5 — the midsegment formula What is the trapezoid midsegment theorem Brian McLogan Open the video →
Lesson 5 — working backward to a base Find a missing length using the midsegment formula Brian McLogan Open the video →

Unit 3 Review Sheet

The review moves through the same progression as the assessment: polygon sums and equations, triangle side/angle inequalities, regular polygons, parallel lines and transversals, parallelograms, and trapezoids with midsegments.

Polygons & triangles

Solve forward and backward with the polygon formulas, find regular-polygon angles, use exterior angles, order sides and angles, and find the interval for a third side.

Lines & quadrilaterals

Name angle pairs, decide congruent vs. supplementary, solve the resulting equations, and apply the parallelogram and trapezoid theorems.

Before you turn in the assessment

  • Every polygon answer checked for the n − 2 step — did you add 2 back at the end?
  • Each angle-pair problem started with the name of the relationship, written down, before any algebra.
  • Same-side interior angles summed to 180° rather than set equal.
  • Every variable substituted back into both expressions it came from.
  • Side and angle orderings matched to the side opposite each angle, not a side touching it.
  • Third-side answers written as an interval with strict inequalities, endpoints excluded.
  • Parallelogram answers using opposite angles congruent and consecutive angles supplementary as a check.
  • Midsegment answers averaged, not summed.

Performance Task: City Design

Parallel lines and transversals, placed in a context where the labels have to convince somebody else.

The build

Design a city map with three parallel streets and two non-parallel transversal streets. Place locations so their intersections demonstrate specific angle relationships. The task also requires a scalene-triangle gas station, a regular-pentagon police station, and a right-triangle courthouse.

Required angle relationships

  • Gas station & restaurant — alternate exterior
  • Home & school — same-side interior
  • Post office & bank — vertical
  • Fire department & police station — corresponding
  • Library & park — alternate interior

Design goal

The point is not just to draw a city. Your labels should make another student able to inspect the map and verify every required angle pair from the street geometry alone.

Where to Go Next

Unit 3 leans on the triangle work from Unit 2 and sets up the congruence proofs in Unit 4.